For a matrix of continous function, does the identity $ \det(e^{A(x)}) = e^{\text{trace}(A(x))} $ still holds?

Question

Assuming that every entry of in the matrix is a continuous function and the matrix is invertible. Would it still be true that $ \det(e^{A(x)}) = e^{\text{trace}(A(x))} $? Would appreciate if somebody could just throw me a yes or no answer. Thank you!