For all prime $\ p\ > \ 2,\ p=2^x \cdot Ord_p(2)+1?\ $ Where $\ x \in \mathbb{Z}_{\geq 0}.\ $
Such as $\ Ord_3 (2) = 2, \ 3=2^0 \cdot 2 + 1$.
Is there some way to prove this?
2026-03-25 07:47:55.1774424875
For all prime $\ p > \ 2,\ p=2^x \cdot Ord_p(2)+1$?
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