I'm struggling on the above question.
I have dy/dx as 4x-5 gradientTangent = 3 gradient normal = -1/3
the corresponding y co-ordinate at x=2 is y=0
I have also created the eqn of the tangent and the normal at this point but I don't really understand what the question is asking for or how to find P.
Now for $x_P$ we have $$4x-5=-\frac{1}{3},$$ which gives $$x_P=\frac{7}{6}.$$ Can you end it now?
I got $$P\left(\frac{7}{6},-\frac{10}{9}\right).$$