for each of the following solve for x and y

Question

Question 1- For each of the following equations 1.1 Solve for x

$$x^2-2xy+y^2=0$$ $$5x^2-3xy-8y^2$$ $$8x^2-5xy-13xy^2=0$$

Answer 1

Use the quadratic formula $$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$$ For 1, $a=1, b=-2y, c=y^2$

Use that same idea for the other 2

EDIT: per @LeeNeverGup and @DanielLittlewood, it is worth mentioning that equation 1 is quite factorable. In particular, quadratics of the form $x^2\pm2xy+y^2$ can be factored as $(x\pm{y})^2$. You solve the equation by setting the equation equal to 0. Thus $$x^2-2xy+y^2=(x+y)^2$$ $$(x-y)^2=0$$ $$x-y=0$$ Thus, $x=y$