This is how I got this equivalence:
$$x < y → y≮x ↔ $$
$$x < y → ~(y < x) ↔ $$
$$(x≤y ∧ x≠y) → ~(y≤x ∧ x≠y) ↔$$
$$(x≤y ∧ x≠y) → (~y≤x ∨ ~x≠y) ↔$$
$$(x≤y ∧ x≠y) → (y≰x ∨ x=y)$$
I would like to know if this is correct
This is how I got this equivalence:
$$x < y → y≮x ↔ $$
$$x < y → ~(y < x) ↔ $$
$$(x≤y ∧ x≠y) → ~(y≤x ∧ x≠y) ↔$$
$$(x≤y ∧ x≠y) → (~y≤x ∨ ~x≠y) ↔$$
$$(x≤y ∧ x≠y) → (y≰x ∨ x=y)$$
I would like to know if this is correct
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