A polyhedron is a convex, three dimensional region bounded by a finite number of polygonal faces.
So is it possible that some of those polygonal faces be concave ? Can concave polygons be used in the process to form a 3D convex region ?
A polyhedron is a convex, three dimensional region bounded by a finite number of polygonal faces.
So is it possible that some of those polygonal faces be concave ? Can concave polygons be used in the process to form a 3D convex region ?
On
If you allow two faces to be coplanar (which would be an unusual admission!), then
you could build a cube of six copies each of the triangle and nonconvex pentagon
shown left below.

But if no two faces are coplanar, then in the neighborhood of a nonconvex point
on the boundary of a nonconvex face, there must be two points determining a segment
(dashed right above) with the segment exterior to the polyhedron. And this means
the polyhedron fails the definition of convexity, and so is itself nonconvex.
No. Every intersection of two convex shapes (such as a convex polyhedron and the plane through one of its faces) is convex.