- I have an n layer (forge-welded) steel billet.
- I fold it i times.
- The total layer count doubles with each fold.
How can i express this with a simple formula?
Is it simply: n*(2^i) ?
For example
13 layers folded 5 times: 13*(2^5)=416
2026-04-25 06:45:35.1777099535
Formula to count layers of damascus steel
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