I have a system: f(x) = $ \begin{cases} \sin x , x \in [0, \pi);\\ 0, x \in [\pi,2\pi].\end{cases}$
Am I right, that I just need to consider a sum of integrals in all formulas?
And period is still $2\pi$ so l = $\pi$.
I have a system: f(x) = $ \begin{cases} \sin x , x \in [0, \pi);\\ 0, x \in [\pi,2\pi].\end{cases}$
Am I right, that I just need to consider a sum of integrals in all formulas?
And period is still $2\pi$ so l = $\pi$.
$$\hat f(n) = \frac{1}{2\pi}\int_{0}^{2\pi} f(x)e^{-inx} dx = \frac{1} {2\pi}\int_{0}^{\pi}sin(x)e^{-inx} dx$$
because $f = 0$ for $x \in [\pi,2\pi]$.
Now write $sin(x) = \frac{e^{ix}-e^{-ix}}{2i}$ and integrate simply.