Fourier series: two different expressions for same period of integration

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I'm currently studying Fourier series. I'm having trouble finding the right expressions for coefficients $a_0, a_n$ and $b_n$. I have 3 sources and 3 different expressions:

My lecture notes states:

$$a_n = \frac{1}{T} \int^T_0 f(t)\cos(\frac{2\pi n}{T}t)dt$$

$$b_n = \frac{1}{T} \int^T_0 f(t)\sin(\frac{2\pi n}{T}t)dt$$

This website says:

$$a_0 = \frac{1}{T} \int^T_0 f(t)dt$$

$$a_n = \frac{2}{T} \int^T_0 f(t)\cos(\frac{2\pi n}{T}t)dt$$

$$b_n = \frac{2}{T} \int^T_0 f(t)\sin(\frac{2\pi n}{T}t)dt$$

and this other shows both expressions for $a_n$ and $b_n$ as correct:

with real part:

$$a_0 = \frac{1}{T} \int^T_0 f(t)dt$$

$$a_n = \frac{2}{T} \int^T_0 f(t)\cos(\frac{2\pi n}{T}t)dt$$

$$b_n = \frac{2}{T} \int^T_0 f(t)\sin(\frac{2\pi n}{T}t)dt$$

without real part:

$$a_0 = \frac{1}{T} \int^T_0 f(t)dt$$

$$a_n = \frac{1}{T} \int^T_0 f(t)\cos(\frac{2\pi n}{T}t)dt$$

$$b_n = \frac{1}{T} \int^T_0 f(t)\sin(\frac{2\pi n}{T}t)dt$$

It is clear that this eqs are not equivalent.

so...

  1. What are the correct expressions?
  2. What it refers when says "with real part" and "without real part"?