I've been stuck at an exercise that wants us to find the Fourier transform for f(x) = cos(x).
The solution being this
Using this formula
I don't know how you go from an integral of sines and cosines to a Dirac delta function, please help.
Use the fact that $\cos(x)=\frac{1}{2}(e^{ix}+e^{-ix})$, and that the Dirac delta function is the Fourier transform of unity:
$$\delta(x)=\frac{1}{2\pi}\int_{-\infty}^{\infty}e^{ikx}dk$$
From here hopefully things will be pretty straightforward.
Copyright © 2021 JogjaFile Inc.
Use the fact that $\cos(x)=\frac{1}{2}(e^{ix}+e^{-ix})$, and that the Dirac delta function is the Fourier transform of unity:
$$\delta(x)=\frac{1}{2\pi}\int_{-\infty}^{\infty}e^{ikx}dk$$
From here hopefully things will be pretty straightforward.