Fourier Transform of $x^{-2}$

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I get that the integral $\int^{+\infty}_{-\infty} t^{-2} e^{i\omega t} dt $ is not convergent, since there is a singularity at $t =0$.

However, I know (Wolfram) that Fourier transform of $f(x) = t^{-2}$ is:

$ g(\omega)=-\sqrt{\frac{\pi}{2}}\omega$

Can somebody explain how is this possible?