$\frac{1}{n^s}-\int_n^{n+1} \frac{\mathrm{d}t}{t^s} \leq \frac{s}{n^{s+1}}$ looking for different proof

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Let $n \in \mathbb{N}_{>0}$ and $s \in \mathbb{R}_{>0}$ then I am interested in the following inequality :

$$\frac{1}{n^s}-\int_n^{n+1} \frac{\mathrm{d}t}{t^s} \leq \frac{s}{n^{s+1}}$$

Here is the way I prove this inequality :

Since $n \geq 1$ then the function : $t \mapsto \frac{1}{t^s}$ is dcreasing on $[n,n+1]$.Hence we have :

$$\frac{1}{n^s}-\int_n^{n+1} \frac{\mathrm{d}t}{t^s} \leq \frac{1}{n^s}-\frac{1}{(n+1)^s}$$

Now using the mean value theorem we get the desired inequality.

I am interested in other proof of this inequality, and if we can find a sharper inequality?