$\frac{1}{x^{\alpha}(\log x)^{\beta}}$ in $L^p((1,\infty))$?

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Consider $$f(x)=\frac{1}{x^{\alpha}(\log x)^{\beta}},$$ $\alpha,\beta\in\mathbb{R}$. For which $\alpha,\beta \in \mathbb{R}$ is $u \in L^p((1,\infty))$, $1\le p\le \infty$?

For $p=1$ I know how to do that (Hölder). $p=\infty$ is no problem too.

My problem is $1<p\le \infty$ .

For 1. I have to find out for which $\alpha, \beta \in \mathbb{R}$ the integral $$\int_1^\infty \left \vert \frac{1}{x^{\alpha}(\log x)^{\beta}}\right\vert^p\,dx$$is finite. I don't know how to estimate, could you give me a hint?

Edit: With the hint I obtain for $1<p<\infty$: $$\int_0^\infty ( \frac{e^{t(1-\alpha)}}{t^{\beta}})^p\,dt=\int_0^1 \frac{e^{t(1-\alpha)p}}{t^{\beta p}}\,dt+\int_1^\infty \frac{e^{t(1-\alpha)p}}{t^{\beta p}}\,dt.$$ How to continue?

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Hint: Substitute (also the limits) in your integral $x\mapsto e^x$. Then you can split the integral in a part around the origin and the rest.