As resolved and how is the graph the phase plane of
$D^{\alpha}y_{1}(t)=2y_{1}(1-\dfrac{y_{1}}{2y_{2}}-\dfrac{y_{1}}{2})$
$D^{\alpha}y_{2}(t)=3y_{2}(1-\dfrac{y_{2}}{2y_{1}}-\dfrac{y_{2}}{2})$
where $y_{1}(0)=0.5$ ;$y_{2}(0)=0.3$
PD: $D^{\alpha}$ is Caputo derivative