Frozen time equilibria are not solutions of nonautonomous system

41 Views Asked by At

I am reading the following textbook:

Introduction to Applied Nonlinear Dynamical Systems and Chaos by Wiggins p.6 (top)

Suppose we have $$\dot{x} = f(x,t), \ \ \ x\in \mathbb{R}^n $$

By implicit function theorem, if we can find $(\bar{x},\bar{t})$ such that $f(\bar{x},\bar{t})=0$ and $D_xf(\bar{x},\bar{t})\neq 0$, then we can find $\bar{x}(t)$, with $\bar{x}(\bar{t})=\bar{x}$ such that $f(\bar{x}(t),t)=0$.

If $\bar{x}(t)$ is a solution of the nonautonomous vector field, then it must be constant in time, i.e., $\dot{\bar{x}}(t)=0$.

Why this is the case? I am confused about it.