$g$ ($h$) interpolates $f$ at $x_0,\ldots x_{n-1}$ ($x_{1},\ldots,x_n$), then $g(x)+\frac{x_0-x}{x_n-x_0}[g(x)-h(x)]$ interpolates $f$

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If $g$ interpolates the function $f$ in $x_0, \ldots x_{n-1}$ and if $h$ interpolates the function $f$ in $x_{1}, x_{2}, \ldots, x_n$, then $$ g(x) + \frac{x_0 - x}{x_n - x_0}\big[ g(x) - h(x)\big] $$ interpolates $f$ in $x_{0}, \ldots, x_{n}$.

I do not know how to show this though. The exercise notes that $g$ and $h$ need not be polynomials.

So if $g$ interpolates $f$ in $x_0, \ldots, x_{n-1}$, then $g(x_i) = y_i = f(x_i)$. Similar for $h$. The difference $g(x) - h(x)$ gives $g(x_n) - h(x_0)$ since they share every other point $x_i$ for $0 < i < n$. From here, I am not sure where to go.