Theorem:
There exists a continuous vector field without singularities on the sphere $S^{n}$ , if only if , $n$ is odd.
I'm really stuck on how to prove this.
Theorem:
There exists a continuous vector field without singularities on the sphere $S^{n}$ , if only if , $n$ is odd.
I'm really stuck on how to prove this.
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Neither are generally true.
If $\frac ab = -\frac 12$, then the right hand side is
$$-\left\lfloor-\frac ab\right\rfloor - 1 = -\left\lfloor\frac 12\right\rfloor - 1 = -0-1 = -1$$
For the first, as a counter example, consider $x = 0$. Then
$$\lfloor x \rfloor = 0 \ne -1$$
For the second, as a counter example, consider $x = -42$. Then
$$\lfloor x \rfloor = -42 \ne -1$$