How can we show that if $G$ is generalized Inverse of $A$ ,
then $G^T$ is generalized Inverse of $A^T$
We have G defined by the properties
$$\begin{align} & AGA = A\\ & GAG = G \\ \end{align}$$
Taking the transpose of both sides of each equation
$$\begin{align} & (AGA)^T = A^TG^TA^T = A^T\\ & (GAG)^T = G^TA^TG^T = G^T \\ \end{align}$$
gets you the property you want.
Copyright © 2021 JogjaFile Inc.
We have G defined by the properties
$$\begin{align} & AGA = A\\ & GAG = G \\ \end{align}$$
Taking the transpose of both sides of each equation
$$\begin{align} & (AGA)^T = A^TG^TA^T = A^T\\ & (GAG)^T = G^TA^TG^T = G^T \\ \end{align}$$
gets you the property you want.