Generalized version of uncountable minus countable is uncountable

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I think my question is generalized version of Uncountable minus countable set is uncountable

I have to show: if $A$ is an infinite set, and $B$ is a subset of $A$, which satisfies $|B|<|A|$, then $|A-B|=|A|$.

I understood the answer to the link above. My textbook advised me to use Axiom of Choice, but I don't know how to apply it into this theorem.

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Recall the axiom of choice implies that summing two cardinals, for infinite cardinals, is the same as taking the $\max$.

Now recall that $|A|=|A-B|+|B|$.