generating function of a0+a1... C((n+4),4)
can anyone help?
small step in proof
thank you so much
please show steps
generating function of a0+a1... C((n+4),4)
can anyone help?
small step in proof
thank you so much
please show steps
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If what you are seeking is a closed form for $$ f(x)=\sum_{n=0}^\infty\binom{n+4}{4}x^n\tag{1} $$ then consider negative binomial coefficients. $(1)$ becomes $$ \begin{align} f(x) &=\sum_{n=0}^\infty\binom{n+4}{4}x^n\\ &=\sum_{n=0}^\infty\binom{n+4}{n}x^n\\ &=\sum_{n=0}^\infty\binom{-5}{n}(-1)^nx^n\\[6pt] &=(1-x)^{-5}\tag{2} \end{align} $$