Given 2 change of basis matrices, find a third

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Given two change of basis matrices, $A>B$ and $B>C$ find the matrix $C>A$

I'm confused about how change of basis matrices work when combining them. I know you can find $B>A$ by finding the inverse matrix, but how can you combine two change of basis matrices? Is it as simple as finding the two inverse matrices then multiplying them together?

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You are correct.

Let $A,B,$ and $C$ be bases. Let $[I]_A^B$ be the change of basis matrix from basis $A$ to $B$.

Then $[I]_A^C = [I]_B^C \; [I]_A^B$ (changing from $A$ to $B$ and then from $B$ to $C$ yields a change from $A$ to $C$).

A consequence of this is that $[I]_A^B [I]_B^A = [I]_B^B =$ identity matrix (changing from $B$ to itself does nothing). Therefore, $[I]_B^A = \left([I]_A^B\right)^{-1}$.

Finally, $[I]_C^A = \left([I]_A^C\right)^{-1} = \left([I]_B^C[I]_A^B\right)^{-1} = \left([I]_A^B\right)^{-1}\left([I]_B^C\right)^{-1}$.