I have a vector, $v$, $ (1,2, 3)^T$ wrt to the basis B and I want to find its coordinates wrt to the basis $\alpha$.
The change of basis matrix, $P_2$ from $\alpha$ to B is given by
$$ \begin{pmatrix} 2 & 1 & -1 \\ 0 & 1 & 0 \\ 1 & 1 & 1 \\ \end{pmatrix} $$
The change of basis matrix, $P_2$ from B to $\alpha$ is given by its inverse which is $$ \begin{pmatrix} {1}/{3} & {-2}/{3} & {1}/{3} \\ 0 & 1 & 0 \\ {-1}/{3} & {-1}/{3} & {2}/{3} \\ \end{pmatrix} $$
The solution given on the worksheet uses $P_1$: $P_1 v$.
However I am confused as this is the change of basis matrix from $\alpha$ to B. I thought that we would want to use $P_2$ as this changes basis from B to $\alpha$.
The full pdf can be found below under question 1:
We have that
$$v_B=P v_\alpha \iff P^{-1}v_B=P^{-1}P v_\alpha \iff v_\alpha=P^{-1}v_B$$
with
$$P=\begin{pmatrix} 2 & 1 & -1 \\ 0 & 1 & 0 \\ 1 & 1 & 1 \\ \end{pmatrix} \quad P^{-1}=\begin{pmatrix} {1}/{3} & {-2}/{3} & {1}/{3} \\ 0 & 1 & 0 \\ {-1}/{3} & {-1}/{3} & {2}/{3} \\ \end{pmatrix}$$
which agrees with the indication given in the linked paper.