Given transformation matrix, what is the area of the resulting figure?

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Given transformation matrix $$T=\begin{bmatrix}10&4\\3&8\end{bmatrix}$$ Applied to the points A(4,2) B(4,6) C(10,2) D(10,6) calculate the area of the resaulting figure. So far I applied the transformation matrix to the given points: \begin{bmatrix}10&4\\3&8\end{bmatrix}.\begin{bmatrix}4&4&10&10\\2&6&2&6\end{bmatrix} = \begin{bmatrix}48&64&108&124\\28&60&46&78\end{bmatrix} and the area before apllying transformation mtrix is 6×4=24 but I do not have any clue how to calculate the area after applying the transformation matrix, so, please help me and explain to me step by step how to find it.

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The determinant scales area by $|\det(T)|$, so you may just calculate the area of the figure in the domain.

The original figure is a rectangle with area $4(6)=24$. Your determinant is $68$. So the area of the resulting figure is $$ 68(24)=1632 $$