$$r_1(t) = \langle t, 2t, 3t\rangle$$ $$r_2(t) = \langle3t, t, 8t\rangle$$
I found $\mathbf{n} = \langle13,1,-5\rangle$
Can I just plug in say $P_0 = (0,0,0)$ and get $13x+y-5z = 0$?
$$r_1(t) = \langle t, 2t, 3t\rangle$$ $$r_2(t) = \langle3t, t, 8t\rangle$$
I found $\mathbf{n} = \langle13,1,-5\rangle$
Can I just plug in say $P_0 = (0,0,0)$ and get $13x+y-5z = 0$?
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