Gradient Vectors as Normal Vectors: How to Find D in Form Ax + By + Cz = D?

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I've got a question that looks like this:

Use the normal gradient vector to determine the equation of the line/plane tangent to the given curve/surface at point P.

$x^4 + xy + y^2 = 19$, P(2,-3)

I know how to use the gradient formula, and end up with an answer of $29x - 4y = ?$. The answer given in my book is 29x + 4y = 70. Where is this 70 coming from? I'm having a lot of trouble trying to figure it out.