I'm looking for a orthonormal basis to 2 polynomials $f,g ∈ \Bbb R_2[x]$
we will define inner product space:
$<f,g>=f\left(0\right)\cdot g\left(0\right)+f\left(1\right)\cdot \:g\left(1\right)+f\left(2\right)\cdot \:\:g\left(2\right)$
I know how to do Gram-Schmidt process to vectors
But how do you make it for polynomial?
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For example in vectors it is easy to see vectors like $\vec v=(0,1),\vec u=(1,0)$
And see that all vectors in $\Bbb R_2$ can appear as linear combination of $\vec v,\vec u$
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But how does it work with polynomials?
Thank you.
2026-03-26 06:19:40.1774505980
Gram-Schmidt process for polynomial space
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1
$<v,v> \, >0$
$<v,v>=0$ iff $v=0$
$<u,v>=\overline{<u,v>}$
$<u,v+w>=<u,v>+<u,w>$
$<u+w,v>=<u,v>+<w,v>$
$<\alpha u,v>=\alpha <u,v>$
Finally given a finite vector space $V$ over $F$, with inner product, then $V$ have a ortonormal basis.
Let $S= \lbrace v_1,v_2, \cdots v_n \rbrace $ basis of $V$.Pick $v_1\in S$. $u_1=v_1$
$u_2=v_2-Proj_{u_1}(v_2)$
$u_3=v_3-Proj_{u_1}(v_3)-Proy_{u_2}(v_3)$
and notice
$u_n=v_n-\sum_{j=1}^{n}{Proy_{u_j}(v_n)}$
And consider $e_i=\frac{u_i}{||U_i||}$
Then the set $U=\lbrace e_1,e_2, \cdots, e_n \rbrace$ is a ortonormal basis of $V$.
In your case you had that the polinomials are a vector space with inner product given by $<p,q>=\sum_{i=0}^{n}{a_ib_i}$ where $a_i,b_i$ are the coeficients of your polinomial(you can comprove it).
Now you only had to follow the process.
I hope that my comment helps you