Consider two real-valued real analytic functions $f$ and $g$. I want to prove that there exists a greatest common divisor $d$, which is a real analytic function. By greatest common divisor, I mean the following:
- Common divisor: There exist real analytic functions $q_1, q_2$ such that $f = dq_1, g = dq_2$, and
- Greateast: If there is any other function $d_1$ that satisfies 1. above, then there exists a real analytic function $q_3$ such that $d = d_1q_3$.
I am guessing that a proof could be derived from the Taylor series expansion, but I am not sure how to proceed.
The relevant data are the roots (with multiplicity).
A GCD of two analytic functions $f$ and $g$ will be an analytic function $h$ such that for each $a \in \mathbb{R}$ one has $\operatorname{ord}_a (h) = \min \{\operatorname{ord}_a (f), \operatorname{ord}_a (g) \}$ where $\operatorname{ord}_a$ denotes the multiplicity of the root at $a$ (setting it $0$ if there is no root).
Put differently the order is the index where the Taylor series expansion around $a$ actually starts.
Algebraically the ring of real analytic functions is a Bézout domain, see for example Ring of analytic functions, meaning every finitely generated ideal is principal and in particular any two elements admit a GCD (see GCD domain)