An integer d is a divisor of a ⇔ ____ | ____.
Equivalently, d is a divisor of a ⇔ ____ mod ____ = _____.
Is it possible for a divisor of a to be bigger than a?
The first blank would be d|a, and I am not sure about the second.
And for the third question, I believe so. But I am not sure how to explain why.
$a$ mod $d$ = 0 <=> $d | a$.
Divisor of $a$ can not be bigger than $a$, because $d | a$ <=> $a = c * d$. If $d > a$, $c < 1$, and it is impossible.