Put $9$ points in a unit square such that the distance between any $2$ points is less or equal to $1$. What is the greatest value of the minimum distance among these $9$ points?
Can it be $\dfrac{\sqrt2}3$? Thanks.
Put $9$ points in a unit square such that the distance between any $2$ points is less or equal to $1$. What is the greatest value of the minimum distance among these $9$ points?
Can it be $\dfrac{\sqrt2}3$? Thanks.
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See https://en.wikipedia.org/wiki/Circle_packing for some results which may be of relevance.
Upper bound
If we ignore the restriction on the separation being no more then $1$ then the greatest minimum separation is $\dfrac{1}{2}$. In this case, two of the separations are as large as $\sqrt 2$ and this suggests that the greatest minimum separation for your problem will be significantly less than $\dfrac{1}{2}$ and therefore less than $\dfrac{\sqrt2}3$.
Lower bound
The convex hull of the nine points has to have diameter less than $1$. Considering the case that this region is a circle, the greatest minimum separation for your problem is $\sin\dfrac{\pi}{8}\approx 0.383$. This is obtained by putting one point in the centre with the other $8$ points equally spaced on a circle of radius $\dfrac{1}{2}$.