(Q,+) abelian group, (Z,+) his subgroup and Q/Z a quotient group.
- Find all subgroups of <$\frac{\hat1}{6}$>,$\frac{\hat1}{6}$ $\in$ Q/Z.
The elements of <$\frac{\hat1}{6}$> are { $\frac{\hat1}{6}$ $\frac{\hat2}{6}$ $\frac{\hat3}{6}$ $\frac{\hat4}{6}$ $\frac{\hat5}{6}$ }. $\frac{\hat6}{6}$ is 1 and $\frac{\hat7}{6}$ is 1+$\frac{\hat1}{6}$ so the order or this group would be 6. Then I'm not really sure what it's subgroups would be. If I take a subset of { $\frac{\hat1}{6}$ $\frac{\hat2}{6}$ $\frac{\hat3}{6}$ $\frac{\hat4}{6}$ $\frac{\hat5}{6}$ } then by summing the elements I'll get one that isn't in the subset so it wouldn't be a subgroup. So are { $\frac{\hat1}{6}$ $\frac{\hat2}{6}$ $\frac{\hat3}{6}$ $\frac{\hat4}{6}$ $\frac{\hat5}{6}$ } and {$\emptyset$} it's only subrougps?
- Is the subgroup <$\frac{\hat5}{7}$,$\frac{\hat8}{9}$> cyclic? If it is find a generator for it.
Here, I didn't understand how the elements of this subgroup should look like... {($\frac{\hat(5+5)}{7}$,$\frac{\hat(8+8)}{9}$)($\frac{\hat(5+5+5)}{7}$,$\frac{\hat(8+8+8)}{9}$)...} I know there might be some theory to explain this but it's really hard for me to understand from abstract theory so this example would help me a lot.