Let the Collatz function be defined as if $x$ even $c(x)=x/2$, if $x$ odd then $c(x)=3x+1$ over the naturals. Each operation is defined as a step. For example $3$ goes $(3,10,5,16,8,4,2,1)$ and takes 8 steps to reach one.
Can anyone find an example for me where the number of steps for starting natural number $x$ to reach one is greater then $260.5+x^.43$?
Here is a graph with the max number of collatz length and the fitted upper bound

slightly more evidence from a slower function on a bigger set.
(function of $460+x^{(1/3)}$)
I conjecture that there is no such number. Is there any other works of this type?

I've searched up to $10^8$ and the closest you get to your bound is at $230631$ which appears in your first graph. Nothing else is even above $240 + x^{.43}$ let alone your bound. $$\{x \in \Bbb{Z}|\quad0<x\le10^8 , \quad f(x) > 240 + x^{.43} \} = \{230631\}$$
As was mentioned in the comments. There are no known results of the type you are asking. I did the search to answer your query for an in-depth search.