Is it possible to take the half derivative of a function in maxima? I tried the following:
(%i1) g: x^3;
3
(%o1) x
(%i2) diff (g, x, 1/2);
1/2
d 3
(%o2) ----- (x )
1/2
dx
It does not seem to compute it. Is there any possible way to calculate this in maxima? Furthermore, is it also possible to take the half integral in some way?