$$\frac{x^3-49x}{ x^4-13x^3+50x^2-56x}$$
I get answer $\frac {x+3} {x-1}$ but my friend say it's wrong I dont understand please help me please
greetings from russia
$$\frac{x^3-49x}{ x^4-13x^3+50x^2-56x}$$
I get answer $\frac {x+3} {x-1}$ but my friend say it's wrong I dont understand please help me please
greetings from russia
$$\frac{x^3-49x} { (x^4-13x^3+50x^2-56x)}=\frac{x(x^2-49)}{x(x^3-13x^2+50x-56)}=\frac{x(x-7)(x+7)}{x(x-2)(x-4)(x-7)}$$