Question

Adjoint of a matrix and inverse of a matrix

score 1.2k · Answer 1 · 2014-11-28 08:09:53

1.2k

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Adjoint of a matrix and inverse of a matrix

Published on 28 Nov 2014 - 8:09

score 1.4k · Answer 2 · 2014-11-28 13:37:14

1.4k

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Proving that $\chi_{T^}=\overline{\chi_T}$ and $m_{T^}=\overline{m_T}$ (characteristic and minimal polynomials of adjoint map)?

Published on 28 Nov 2014 - 13:37

score 10.2k · Answer 3 · 2014-11-29 06:33:59

10.2k

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Finding the determinant of a matrix given the adjoint

Published on 29 Nov 2014 - 6:33

score 1.8k · Answer 4 · 2014-12-06 21:39:15

1.8k

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Schur decomposition of a matrix with distinct eigenvalues is almost unique

Published on 06 Dec 2014 - 21:39

score 1.7k · Answer 5 · 2014-12-09 09:06:33

1.7k

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Green's operator, differential forms

Published on 09 Dec 2014 - 9:06

score 5.4k · Answer 6 · 2014-12-10 01:15:21

5.4k

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Kernel of adjoint and orthogonal complement images

Published on 10 Dec 2014 - 1:15

score 58 · Answer 7 · 2014-12-15 01:31:54

58

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Adjoint linear operators and inner products question; why does $\langle T(x),T(x)\rangle =\langle T^*T(x),x\rangle $?

Published on 15 Dec 2014 - 1:31

score 59 · Answer 8 · 2014-12-19 14:30:10

59

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Change of base - Hermitic matrices

Published on 19 Dec 2014 - 14:30

score 1.7k · Answer 9 · 2014-12-21 00:57:03

1.7k

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Prove that $T^*$ is injective iff $ImT$ Is dense

Published on 21 Dec 2014 - 0:57

score 969 · Answer 10 · 2014-12-31 19:12:42

969

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Existence of adjoint of the inverse

Published on 31 Dec 2014 - 19:12

score 132 · Answer 11 · 2019-10-04 15:19:37

132

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What is the square-root of the nonnegative self-adjoint operator $L^2\to L^2,f\mapsto\int f$?

Published on 04 Oct 2019 - 15:19

score 214 · Answer 12 · 2019-10-04 17:14:49

214

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The tensor product of a Hilbert space with a finite dimensional vector space and the adjoint operator on that space

Published on 04 Oct 2019 - 17:14

score 98 · Answer 13 · 2019-10-06 18:42:30

98

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Can we show that $\sup_{\left\|x\right\|_H=1}\langle Ax,x\rangle_H$ is attained at the supremum of $\sigma(A+A^\ast)$?

Published on 06 Oct 2019 - 18:42

score 45 · Answer 14 · 2019-10-08 10:16:26

45

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for linear Operators is it true that $(A^*)^{-1}=I$, whrere $I$ is the neutral element?

Published on 08 Oct 2019 - 10:16

score 222 · Answer 15 · 2019-10-08 14:28:55

222

Views

Every weak*-closed subspace of the dual space of a normed space is the range of an adjoint operator

Published on 08 Oct 2019 - 14:28

List Question

Adjoint of a matrix and inverse of a matrix

Proving that $\chi_{T^}=\overline{\chi_T}$ and $m_{T^}=\overline{m_T}$ (characteristic and minimal polynomials of adjoint map)?

Finding the determinant of a matrix given the adjoint

Schur decomposition of a matrix with distinct eigenvalues is almost unique

Green's operator, differential forms

Kernel of adjoint and orthogonal complement images

Adjoint linear operators and inner products question; why does $\langle T(x),T(x)\rangle =\langle T^*T(x),x\rangle $?

Change of base - Hermitic matrices

Prove that $T^*$ is injective iff $ImT$ Is dense

Existence of adjoint of the inverse

What is the square-root of the nonnegative self-adjoint operator $L^2\to L^2,f\mapsto\int f$?

The tensor product of a Hilbert space with a finite dimensional vector space and the adjoint operator on that space

Can we show that $\sup_{\left\|x\right\|_H=1}\langle Ax,x\rangle_H$ is attained at the supremum of $\sigma(A+A^\ast)$?

for linear Operators is it true that $(A^*)^{-1}=I$, whrere $I$ is the neutral element?

Every weak*-closed subspace of the dual space of a normed space is the range of an adjoint operator

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