Question

Brezis' exercise 6.24.3: prove that $(0,1) \subset \rho(T)$ IFF $\langle Tu, u \rangle \leq |T u|^2$ for all $u\in H$

score 39 · Answer 1 · 2023-08-02 20:32:43

39

Views

Brezis' exercise 6.24.3: prove that $(0,1) \subset \rho(T)$ IFF $\langle Tu, u \rangle \leq |T u|^2$ for all $u\in H$

Published on 02 Aug 2023 - 20:32

score 69 · Answer 2 · 2026-03-25 18:48:12

69

Views

If $T$ is a closable densely defined operator then $T^* = \overline{(T^*)} = T^{***} = (\overline{T})^*$

Published on 25 Mar 2026 - 18:48

score 56 · Answer 3 · 2026-03-26 04:52:36

56

Views

For an essentially self-adjoint operator $T$, why is $(T^{**})^* = T^{**}$?

Published on 26 Mar 2026 - 4:52

score 54 · Answer 4 · 2026-03-25 18:49:04

54

Views

If $T$ is a symmetric densely defined operator its adjoint $T^*$ is a closed extension of $T$

Published on 25 Mar 2026 - 18:49

score 96 · Answer 5 · 2023-08-09 05:29:11

96

Views

Convolution and difference convolution adjoint

Published on 09 Aug 2023 - 5:29

score 78 · Answer 6 · 2023-08-10 17:24:29

78

Views

Eigenvectors of any arbitrary matrix is same as its adjoint.

Published on 10 Aug 2023 - 17:24

score 38 · Answer 7 · 2023-08-15 12:42:12

38

Views

Bounded orbit in Adjoint operator $T^*$ implies bounded orbit in $T$?

Published on 15 Aug 2023 - 12:42

score 133 · Answer 8 · 2023-08-15 15:06:58

133

Views

Domain of the adjoint operator of a bounded operator (on a Hilbert space). (Experimental physicist)

Published on 15 Aug 2023 - 15:06

score 28 · Answer 9 · 2026-03-23 03:52:27

28

Views

Action of the adjoint operator in tangent space

Published on 23 Mar 2026 - 3:52

score 184 · Answer 10 · 2026-03-26 17:33:08

184

Views

What is the adjoint of the curl operator?

Published on 26 Mar 2026 - 17:33

score 63 · Answer 11 · 2023-09-26 00:12:11

63

Views

Properties of Cesàro Operator in $L^2$

Published on 26 Sep 2023 - 0:12

score 37 · Answer 12 · 2023-09-27 21:28:45

37

Views

Finding the conjugate of an operator between the Banach spaces $\ell_{p}$

Published on 27 Sep 2023 - 21:28

score 96 · Answer 13 · 2023-10-02 07:14:46

96

Views

Why do we need the operator to be densely defined for defining adjoint?

Published on 02 Oct 2023 - 7:14

score 39 · Answer 14 · 2023-10-21 04:37:38

39

Views

Let $V$ be finite dimensional complex vector space, $d:V\to V$ be linear map such that $d^2=0$ and $\Delta=dd^{\star}+d^{\star}d$. Prove the following

Published on 21 Oct 2023 - 4:37

score 73 · Answer 15 · 2023-10-25 20:08:27

73

Views

Normal operators, verification

Published on 25 Oct 2023 - 20:08

List Question

Brezis' exercise 6.24.3: prove that $(0,1) \subset \rho(T)$ IFF $\langle Tu, u \rangle \leq |T u|^2$ for all $u\in H$

If $T$ is a closable densely defined operator then $T^* = \overline{(T^*)} = T^{***} = (\overline{T})^*$

For an essentially self-adjoint operator $T$, why is $(T^{**})^* = T^{**}$?

If $T$ is a symmetric densely defined operator its adjoint $T^*$ is a closed extension of $T$

Convolution and difference convolution adjoint

Eigenvectors of any arbitrary matrix is same as its adjoint.

Bounded orbit in Adjoint operator $T^*$ implies bounded orbit in $T$?

Domain of the adjoint operator of a bounded operator (on a Hilbert space). (Experimental physicist)

Action of the adjoint operator in tangent space

What is the adjoint of the curl operator?

Properties of Cesàro Operator in $L^2$

Finding the conjugate of an operator between the Banach spaces $\ell_{p}$

Why do we need the operator to be densely defined for defining adjoint?

Let $V$ be finite dimensional complex vector space, $d:V\to V$ be linear map such that $d^2=0$ and $\Delta=dd^{\star}+d^{\star}d$. Prove the following

Normal operators, verification

Trending Questions

Popular # Hahtags

Popular Questions