List questions from adjoint-operators

Published on 08 Mar 2015 - 17:25

1.6k

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Find a general 2x2 matrix where A = adj(A)

Published on 19 Mar 2015 - 19:46

189

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Showing that if $A$ is closed, then $A^\ast A$ is self-adjoint

Published on 24 Mar 2015 - 20:38

335

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relation eigenvalue and adj(A-λI)

Published on 27 Mar 2015 - 4:46

120

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Quadratic Functional Differentiability

Published on 27 Mar 2015 - 18:50

470

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let $\dim(ker (A - \lambda I)) = 1$. why is $adj(A - \lambda I) \ne 0$

Published on 31 Mar 2015 - 13:47

544

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Adjoint of Exponential Map

Published on 02 Apr 2015 - 2:51

68

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Relation between a function and its norm

Published on 27 Mar 2026 - 19:12

45

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About the self-adjoint extension of an operator.

Published on 16 Apr 2015 - 1:38

26.3k

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$A^{-1}$ has integer entries if and only if the ${\rm det}\ (A) =\pm 1$

Published on 20 Apr 2015 - 23:45

2.6k

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Adjoint operator on Banach space

Published on 28 Mar 2026 - 3:32

756

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Product of compact, bounded and self adjoint operator.

Published on 30 Apr 2015 - 0:52

772

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$T \in B(X,Y)$ is an isometry if and only if $T^*$ is an isometry

Published on 01 May 2015 - 22:53

1.4k

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Proof that All Entries in an Inverse Matrix are Integers

Published on 03 May 2015 - 22:26

2.1k

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Show $ \langle Tx,x \rangle \in \Bbb R\ \forall x \in H\ \implies T$ is self-adjoint

Published on 11 May 2015 - 22:29

List Question

Calculate inverse of matrix

Find a general 2x2 matrix where A = adj(A)

Showing that if $A$ is closed, then $A^\ast A$ is self-adjoint

relation eigenvalue and adj(A-λI)

Quadratic Functional Differentiability

let $\dim(ker (A - \lambda I)) = 1$. why is $adj(A - \lambda I) \ne 0$

Adjoint of Exponential Map

Relation between a function and its norm

About the self-adjoint extension of an operator.

$A^{-1}$ has integer entries if and only if the ${\rm det}\ (A) =\pm 1$

Adjoint operator on Banach space

Product of compact, bounded and self adjoint operator.

$T \in B(X,Y)$ is an isometry if and only if $T^*$ is an isometry

Proof that All Entries in an Inverse Matrix are Integers

Show $ \langle Tx,x \rangle \in \Bbb R\ \forall x \in H\ \implies T$ is self-adjoint

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