Question

Direct product of modules and the axiom of choice

score 52 · Answer 1 · 2026-03-28 16:26:25

52

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Direct product of modules and the axiom of choice

Published on 28 Mar 2026 - 16:26

score 114 · Answer 2 · 2021-11-13 18:25:39

114

Views

$\kappa< \kappa^ {\operatorname{cf}(\kappa)}$ in ZF

Published on 13 Nov 2021 - 18:25

score 61 · Answer 3 · 2021-11-15 16:06:23

61

Views

How Zorn's Lemma implies Axiom of Choice

Published on 15 Nov 2021 - 16:06

score 49 · Answer 4 · 2026-03-30 12:23:39

49

Views

Axiom schema of Replacement analogue for Von Neumann stage

Published on 30 Mar 2026 - 12:23

score 37 · Answer 5 · 2021-11-19 22:52:47

37

Views

Is the existence of an uncountable proper subgroup of the real numbers under addition provable without AC?

Published on 19 Nov 2021 - 22:52

score 164 · Answer 6 · 2021-11-24 07:56:46

164

Views

Is Choice over definable sets equivalent to AC?

Published on 24 Nov 2021 - 7:56

score 91 · Answer 7 · 2021-11-27 19:39:53

91

Views

Can ZF be subsumed in ZFC?

Published on 27 Nov 2021 - 19:39

score 150 · Answer 8 · 2021-11-29 04:25:25

150

Views

Understanding axiom of choice from examples

Published on 29 Nov 2021 - 4:25

score 20 · Answer 9 · 2021-11-29 09:50:12

20

Views

Finiteness of a set and axiom of choice

Published on 29 Nov 2021 - 9:50

score 66 · Answer 10 · 2021-12-01 21:02:48

66

Views

How can there only be continuum many measurable functions if it is consistent with ZF that all real functions are measurable?

Published on 01 Dec 2021 - 21:02

score 74 · Answer 11 · 2021-12-02 08:35:22

74

Views

Can we prove the existence of a non-measurable subset using an uncountable well-ordered subset without $\sf DC$?

Published on 02 Dec 2021 - 8:35

score 92 · Answer 12 · 2021-12-02 10:24:48

92

Views

If $Y$ is a regular, then $\delta(X,Y)$ with compact-open topology is regular

Published on 02 Dec 2021 - 10:24

score 210 · Answer 13 · 2026-03-29 05:11:47

210

Views

Proving Sierpinski’s result without choice.

Published on 29 Mar 2026 - 5:11

score 49 · Answer 14 · 2026-03-29 03:28:37

49

Views

A question regarding the upward implications between versions of the infinite Ramsey theorem over $\sf ZF$.

Published on 29 Mar 2026 - 3:28

score 75 · Answer 15 · 2021-12-12 13:36:35

75

Views

In the Garling's proof of 'AC implies Zorn's lemma'

Published on 12 Dec 2021 - 13:36

List Question

Direct product of modules and the axiom of choice

$\kappa< \kappa^ {\operatorname{cf}(\kappa)}$ in ZF

How Zorn's Lemma implies Axiom of Choice

Axiom schema of Replacement analogue for Von Neumann stage

Is the existence of an uncountable proper subgroup of the real numbers under addition provable without AC?

Is Choice over definable sets equivalent to AC?

Can ZF be subsumed in ZFC?

Understanding axiom of choice from examples

Finiteness of a set and axiom of choice

How can there only be continuum many measurable functions if it is consistent with ZF that all real functions are measurable?

Can we prove the existence of a non-measurable subset using an uncountable well-ordered subset without $\sf DC$?

If $Y$ is a regular, then $\delta(X,Y)$ with compact-open topology is regular

Proving Sierpinski’s result without choice.

A question regarding the upward implications between versions of the infinite Ramsey theorem over $\sf ZF$.

In the Garling's proof of 'AC implies Zorn's lemma'

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