Question

Ordinal enumeration in ordered Mostowski model - does it not need the global choice?

score 131 · Answer 1 · 2016-02-09 04:41:19

131

Views

Ordinal enumeration in ordered Mostowski model - does it not need the global choice?

Published on 09 Feb 2016 - 4:41

score 6.1k · Answer 2 · 2016-02-11 03:47:34

6.1k

Views

Why is the statement "all vector space have a basis" is equivalent to the axiom of choice?

Published on 11 Feb 2016 - 3:47

score 115 · Answer 3 · 2016-02-14 19:26:57

115

Views

Every set of pairwise disjoint sets has a choice function implies AC

Published on 14 Feb 2016 - 19:26

score 1.2k · Answer 4 · 2016-02-14 21:28:51

1.2k

Views

Axiom of choice - Equivalence relation - Representatives

Published on 14 Feb 2016 - 21:28

score 802 · Answer 5 · 2016-02-16 08:44:41

802

Views

Does the axiom of choice have any use for finite sets?

Published on 16 Feb 2016 - 8:44

score 406 · Answer 6 · 2016-02-17 20:29:19

406

Views

How does equality $\mathfrak{m}^\mathfrak{m} = 2^\mathfrak{m}$ in $\sf{ZF}$ relate to the axiom of choice?

Published on 17 Feb 2016 - 20:29

score 155 · Answer 7 · 2016-02-21 05:30:54

155

Views

How to avoid the Axiom of Choice in proving Higman's Lemma?

Published on 21 Feb 2016 - 5:30

score 34 · Answer 8 · 2026-04-03 15:12:33

34

Views

Is the axiom of countable choice needed for the proof of this special case of equivalence of limit definitions?

Published on 03 Apr 2026 - 15:12

score 150 · Answer 9 · 2026-03-27 03:43:04

150

Views

A doubt in the proof of "AC implies law of excluded middle"

Published on 27 Mar 2026 - 3:43

score 225 · Answer 10 · 2016-02-28 08:32:47

225

Views

Proof that well-ordering implies choice

Published on 28 Feb 2016 - 8:32

score 286 · Answer 11 · 2016-03-03 14:08:07

286

Views

Partitioning an infinite set into two equinumerous subsets

Published on 03 Mar 2016 - 14:08

score 522 · Answer 12 · 2016-03-06 23:30:29

522

Views

If $X$ is a metric, then $X$ is compact if and only if $X$ is sequentially compact - axiom of choice usage

Published on 06 Mar 2016 - 23:30

score 1.8k · Answer 13 · 2016-03-09 01:44:26

1.8k

Views

Hausdorff Maximal Principle and Axiom of Choice

Published on 09 Mar 2016 - 1:44

score 70 · Answer 14 · 2026-02-23 14:03:20

70

Views

Does this minimum exist? Modified Ascoli theorem without countable choice

Published on 23 Feb 2026 - 14:03

score 393 · Answer 15 · 2016-03-09 10:09:35

393

Views

Set Theory - Prove that there is a function $f:\omega\to X$ such that $f(n)<f(n+)$ when $X$ has no maximal element.

Published on 09 Mar 2016 - 10:09

List Question

Ordinal enumeration in ordered Mostowski model - does it not need the global choice?

Why is the statement "all vector space have a basis" is equivalent to the axiom of choice?

Every set of pairwise disjoint sets has a choice function implies AC

Axiom of choice - Equivalence relation - Representatives

Does the axiom of choice have any use for finite sets?

How does equality $\mathfrak{m}^\mathfrak{m} = 2^\mathfrak{m}$ in $\sf{ZF}$ relate to the axiom of choice?

How to avoid the Axiom of Choice in proving Higman's Lemma?

Is the axiom of countable choice needed for the proof of this special case of equivalence of limit definitions?

A doubt in the proof of "AC implies law of excluded middle"

Proof that well-ordering implies choice

Partitioning an infinite set into two equinumerous subsets

If $X$ is a metric, then $X$ is compact if and only if $X$ is sequentially compact - axiom of choice usage

Hausdorff Maximal Principle and Axiom of Choice

Does this minimum exist? Modified Ascoli theorem without countable choice

Set Theory - Prove that there is a function $f:\omega\to X$ such that $f(n)<f(n+)$ when $X$ has no maximal element.

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