List questions from binomial-coefficients

Published on 06 Dec 2014 - 0:35

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Closed Form for a Sequence

Published on 26 Mar 2026 - 16:11

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How many positive integer solutions are there to the equation $(a + b + c + d) < N$?

Published on 07 Dec 2014 - 1:34

57

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proof of summation using $\displaystyle \binom{n}{r}$

Published on 29 Mar 2026 - 6:30

279

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Multinomial identity - guidance needed

Published on 25 Mar 2026 - 17:44

271

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A finite binomial sum

Published on 10 Dec 2014 - 6:02

195

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Finite natural summation that leads to double exponential results

Published on 30 Mar 2026 - 3:20

84

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Lie derivatives of vector fields and the binomial expansion

Published on 10 Dec 2014 - 13:40

437

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Probability involving bread and jam!

Published on 29 Mar 2026 - 6:30

2.1k

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Growth of binomial coefficient

Published on 10 Dec 2014 - 21:19

98

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General solution for a combinatorial problem

Published on 11 Dec 2014 - 6:49

55

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If $a_n = \sum^n_{r=0} \frac{(\ln10)^n}{r! (n-r)!}$ for $n \geq 0$ .....

Published on 11 Dec 2014 - 14:34

441

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Prime factors of binomials

Published on 11 Dec 2014 - 15:39

4.3k

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Generating functions and central binomial coefficient

Published on 31 Mar 2026 - 12:53

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How prove this identity$\sum_{k=0}^{n}\binom{2k}{k}\binom{n+k}{2k}(s-t)^{n-k}t^k=\sum_{k=0}^{n}\binom{n}{k}^2s^{n-k}t^k$

Published on 12 Dec 2014 - 7:59

List Question

A binomial inequality

Closed Form for a Sequence

How many positive integer solutions are there to the equation $(a + b + c + d) < N$?

proof of summation using $\displaystyle \binom{n}{r}$

Multinomial identity - guidance needed

A finite binomial sum

Finite natural summation that leads to double exponential results

Lie derivatives of vector fields and the binomial expansion

Probability involving bread and jam!

Growth of binomial coefficient

General solution for a combinatorial problem

If $a_n = \sum^n_{r=0} \frac{(\ln10)^n}{r! (n-r)!}$ for $n \geq 0$ .....

Prime factors of binomials

Generating functions and central binomial coefficient

How prove this identity$\sum_{k=0}^{n}\binom{2k}{k}\binom{n+k}{2k}(s-t)^{n-k}t^k=\sum_{k=0}^{n}\binom{n}{k}^2s^{n-k}t^k$

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