Question

Sufficient conditions on $M$ such that the intersection of infinitely many $\mathfrak{m} M$, $\mathfrak{m}$ maximal ideal, is zero?

score 31 · Answer 1 · 2026-03-30 15:17:16

Sufficient conditions on $M$ such that the intersection of infinitely many $\mathfrak{m} M$, $\mathfrak{m}$ maximal ideal, is zero?

score 1.3k · Answer 2 · 2026-03-25 10:56:53

1.3k

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174

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Derivations of a formally smooth artinian ring

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71

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67

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score 169 · Answer 7 · 2019-01-24 09:11:52

169

Views

Geometric interpretation of $M/M^2$ and $M^n /M^{n+1}$, for $M$ maximal ideal of a DVR

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score 49 · Answer 8 · 2026-03-30 16:48:36

49

Views

Is $\operatorname{Hom}_R(S,R)$ as an $S$-module torsionless?

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345

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161

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236

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score 419 · Answer 12 · 2019-01-25 10:52:23

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217

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score 34 · Answer 15 · 2026-03-26 02:56:21

34

Views

There exists an element $x$ of $M$ such that $W^{-1}R\dfrac{x}{1}=W^{-1}Rz$ and $\operatorname{ann}_R x=\operatorname{ann}_{W^{-1}R} z\cap R$

Published on 26 Mar 2026 - 2:56

List Question

Sufficient conditions on $M$ such that the intersection of infinitely many $\mathfrak{m} M$, $\mathfrak{m}$ maximal ideal, is zero?

$K[X^2,X^3]\subset K[X]$ is a Noetherian domain and all its prime ideals are maximal

Derivations of a formally smooth artinian ring

Why is this a filtered category? Localization of rings.

Dimension of affine affine algebras as a module

How can we have he similar decomposition of $ \mathbb{Q}_p$ and $\mathbb{Q}_p(\zeta_p)$?

Geometric interpretation of $M/M^2$ and $M^n /M^{n+1}$, for $M$ maximal ideal of a DVR

Is $\operatorname{Hom}_R(S,R)$ as an $S$-module torsionless?

Is the functor $\text{Spec}:(\mathsf{CRing})^{\text{op}}\to\mathsf{Set}$ right exact?

ideal extension in polynomial ring over quotient field

On integral closedness of formal power series ring over an integrally closed domain satisfying Krull intersection principle

Tensor square of a torsion-free module ($R$ domain)

Finite Algebras and Grobner Bases

Intuition and technique for (strict) Henselization of nodal cubic at node

There exists an element $x$ of $M$ such that $W^{-1}R\dfrac{x}{1}=W^{-1}Rz$ and $\operatorname{ann}_R x=\operatorname{ann}_{W^{-1}R} z\cap R$

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