Question

If $J = (a_1, a_2, \ldots)$ is dense, does that imply $J = (a_1^{n_1}, a_2^{n_2}, \ldots)$ is dense too?

score 48 · Answer 1 · 2026-04-15 13:26:58

48

Views

If $J = (a_1, a_2, \ldots)$ is dense, does that imply $J = (a_1^{n_1}, a_2^{n_2}, \ldots)$ is dense too?

Published on 15 Apr 2026 - 13:26

score 978 · Answer 2 · 2026-04-10 18:46:02

978

Views

Confusion about definition of height of prime ideal. How do minimal prime ideals have height 0?

Published on 10 Apr 2026 - 18:46

score 82 · Answer 3 · 2026-04-13 19:50:16

82

Views

$\Omega_{L/k}=L\otimes_K\Omega_{K/k}$ when $L/K$ finite separable

Published on 13 Apr 2026 - 19:50

score 173 · Answer 4 · 2026-04-10 23:33:25

173

Views

Homomorphisms from abelian groups to $S^1$ separate points

Published on 10 Apr 2026 - 23:33

score 63 · Answer 5 · 2026-03-25 20:40:10

63

Views

Question about parameter

Published on 25 Mar 2026 - 20:40

score 79 · Answer 6 · 2026-04-16 07:52:49

79

Views

Let $A$ be a ring with maximal ideal $m$. $\hat{A},\hat{M}$ completion and $A-$module $M$. $M\to\hat{M}$ image dense?

Published on 16 Apr 2026 - 7:52

score 90 · Answer 7 · 2026-04-14 07:18:10

90

Views

$\mathrm{Hom}(N,\bullet)$ is a functor from (($R$-alg)) to ((?))

Published on 14 Apr 2026 - 7:18

score 60 · Answer 8 · 2026-03-29 04:51:46

60

Views

A variation on Keller's theorem

Published on 29 Mar 2026 - 4:51

score 235 · Answer 9 · 2026-04-27 12:28:16

235

Views

Every element of a ring $A$ is integral over the ring $A$. How?

Published on 27 Apr 2026 - 12:28

score 693 · Answer 10 · 2026-04-12 17:52:00

693

Views

Is ring of $S$-integers a Dedekind domain?

Published on 12 Apr 2026 - 17:52

score 243 · Answer 11 · 2026-04-11 15:28:22

243

Views

Reduced scheme and covering with non affines reduced schemes

Published on 11 Apr 2026 - 15:28

score 67 · Answer 12 · 2026-04-09 06:03:22

67

Views

A characterization of a nilpotent endomorphism

Published on 09 Apr 2026 - 6:03

score 89 · Answer 13 · 2026-04-23 17:04:40

Let $A\subset B$ be an integral ring extension, and $p\in\operatorname{Spec}A$. Then there exists $q\in\operatorname{Spec}B$ such that $q\cap A=p$.

score 78 · Answer 14 · 2026-04-17 12:01:12

78

Views

Question about ring homomorphism within a ring.

Published on 17 Apr 2026 - 12:01

score 220 · Answer 15 · 2026-04-16 09:07:06

220

Views

Prove that $\mathrm{ht}(P/Ra)=\mathrm{ht}(P) -1$

Published on 16 Apr 2026 - 9:07

List Question

If $J = (a_1, a_2, \ldots)$ is dense, does that imply $J = (a_1^{n_1}, a_2^{n_2}, \ldots)$ is dense too?

Confusion about definition of height of prime ideal. How do minimal prime ideals have height 0?

$\Omega_{L/k}=L\otimes_K\Omega_{K/k}$ when $L/K$ finite separable

Homomorphisms from abelian groups to $S^1$ separate points

Question about parameter

Let $A$ be a ring with maximal ideal $m$. $\hat{A},\hat{M}$ completion and $A-$module $M$. $M\to\hat{M}$ image dense?

$\mathrm{Hom}(N,\bullet)$ is a functor from (($R$-alg)) to ((?))

A variation on Keller's theorem

Every element of a ring $A$ is integral over the ring $A$. How?

Is ring of $S$-integers a Dedekind domain?

Reduced scheme and covering with non affines reduced schemes

A characterization of a nilpotent endomorphism

Let $A\subset B$ be an integral ring extension, and $p\in\operatorname{Spec}A$. Then there exists $q\in\operatorname{Spec}B$ such that $q\cap A=p$.

Question about ring homomorphism within a ring.

Prove that $\mathrm{ht}(P/Ra)=\mathrm{ht}(P) -1$

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