Question

$K$ is a linear compact operator on Hilbert space $H$. Will the image of $I-K$ on every closed subspace of $H$ be also closed?

score 185 · Answer 1 · 2013-04-06 21:15:43

185

Views

$K$ is a linear compact operator on Hilbert space $H$. Will the image of $I-K$ on every closed subspace of $H$ be also closed?

Published on 06 Apr 2013 - 21:15

score 1.8k · Answer 2 · 2013-04-07 19:31:52

1.8k

Views

Invertibility of compact operators

Published on 07 Apr 2013 - 19:31

score 1.3k · Answer 3 · 2013-04-08 23:33:52

1.3k

Views

Strong operator convergence and adjoint operator

Published on 08 Apr 2013 - 23:33

score 232 · Answer 4 · 2013-04-16 18:31:06

232

Views

Show for compact operator $K$, if $||Kf|| < ||f|| \forall f$, then $||K|| < 1$.

Published on 16 Apr 2013 - 18:31

score 1.7k · Answer 5 · 2013-04-29 14:21:27

1.7k

Views

The set of compact linear operators is a subspace of the set of bounded linear operators

Published on 29 Apr 2013 - 14:21

score 656 · Answer 6 · 2013-05-05 06:18:16

656

Views

Showing that the inverse of the perturbation of a compact operator by a bounded operator remains compact.

Published on 05 May 2013 - 6:18

score 2k · Answer 7 · 2013-05-13 17:13:30

2k

Views

Is restriction of compact operator always compact?

Published on 13 May 2013 - 17:13

score 1.3k · Answer 8 · 2013-05-14 01:01:02

1.3k

Views

Showing that smoothing operators are compact

Published on 14 May 2013 - 1:01

score 78 · Answer 9 · 2013-05-23 00:13:03

78

Views

About compact operator

Published on 23 May 2013 - 0:13

score 236 · Answer 10 · 2013-05-25 10:29:57

236

Views

Compact linear operator on a separable Hilbert space is approximately of finite dimension

Published on 25 May 2013 - 10:29

score 988 · Answer 11 · 2013-05-25 19:52:22

988

Views

Criteria of compactness of an operator

Published on 25 May 2013 - 19:52

score 105 · Answer 12 · 2013-05-30 02:44:57

105

Views

Solution to operator equation, surjectivity

Published on 30 May 2013 - 2:44

score 3.5k · Answer 13 · 2013-05-30 22:29:33

3.5k

Views

Invertible operator

Published on 30 May 2013 - 22:29

score 254 · Answer 14 · 2013-06-02 17:35:09

254

Views

Norm operator and compactness

Published on 02 Jun 2013 - 17:35

score 196 · Answer 15 · 2013-06-09 08:40:08

196

Views

How to show that a sequence in $l^{2}$ has a convergent subseqence after the action of an operator.

Published on 09 Jun 2013 - 8:40

List Question

$K$ is a linear compact operator on Hilbert space $H$. Will the image of $I-K$ on every closed subspace of $H$ be also closed?

Invertibility of compact operators

Strong operator convergence and adjoint operator

Show for compact operator $K$, if $||Kf|| < ||f|| \forall f$, then $||K|| < 1$.

The set of compact linear operators is a subspace of the set of bounded linear operators

Showing that the inverse of the perturbation of a compact operator by a bounded operator remains compact.

Is restriction of compact operator always compact?

Showing that smoothing operators are compact

About compact operator

Compact linear operator on a separable Hilbert space is approximately of finite dimension

Criteria of compactness of an operator

Solution to operator equation, surjectivity

Invertible operator

Norm operator and compactness

How to show that a sequence in $l^{2}$ has a convergent subseqence after the action of an operator.

Trending Questions

Popular # Hahtags

Popular Questions