Question

Show these operators converge to a particular limit

score 129 · Answer 1 · 2014-03-08 11:14:10

129

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Show these operators converge to a particular limit

Published on 08 Mar 2014 - 11:14

score 4.2k · Answer 2 · 2014-03-11 05:10:36

4.2k

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Show the Volterra Operator is compact using only the definition of compact

Published on 11 Mar 2014 - 5:10

score 407 · Answer 3 · 2017-04-13 00:43:36

407

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Let $V\in\mathbb{B}(H,K)$ where $H,K$ are Hilberts spaces. Then $V$ is partial isometry if and only if $V^*$ is partial isometry.

Published on 13 Apr 2017 - 0:43

score 95 · Answer 4 · 2017-04-15 06:24:41

95

Views

To prove for each sequence $(x_n)$ in $A$ , $T(x_n)$ has a Cauchy subsequence.

Published on 15 Apr 2017 - 6:24

score 281 · Answer 5 · 2017-04-15 14:54:21

281

Views

Fixed point of compact operator in Banach space

Published on 15 Apr 2017 - 14:54

score 368 · Answer 6 · 2017-04-17 18:27:01

368

Views

Proving that $K:l_2 \to l_2$ is a compact self-adjoint operator

Published on 17 Apr 2017 - 18:27

score 133 · Answer 7 · 2026-03-28 00:56:24

133

Views

How will covariance matrix converge to the covariance function, especially in the aspect of eigenvalues and eigenvectors

Published on 28 Mar 2026 - 0:56

score 498 · Answer 8 · 2017-04-24 21:02:39

498

Views

Universal $C^\ast$-algebra generated by the unilateral shift.

Published on 24 Apr 2017 - 21:02

score 105 · Answer 9 · 2017-04-25 13:49:13

105

Views

why is it a compact operator

Published on 25 Apr 2017 - 13:49

score 976 · Answer 10 · 2017-04-29 16:59:23

976

Views

What is the closure of the space of compact operators , on Hilbert space , in the space of bounded operators , under strong operator topology ?

Published on 29 Apr 2017 - 16:59

score 81 · Answer 11 · 2017-05-01 07:09:35

$H$ be a complex Hilbert space , $T: H \to H$ be a compact operator , if $c$ is a eigen-value of $T$ , is $\bar c$ an eigenvalue of $T^*$?

score 783 · Answer 12 · 2017-05-01 17:43:08

783

Views

Prove that the following operator is compact.

Published on 01 May 2017 - 17:43

score 131 · Answer 13 · 2017-05-03 13:09:59

131

Views

Non-compact operator with compact derivative

Published on 03 May 2017 - 13:09

score 1.9k · Answer 14 · 2017-05-07 16:35:04

1.9k

Views

Question on why Hilbert-Schmidt operator definition is independent of the choice of basis

Published on 07 May 2017 - 16:35

score 763 · Answer 15 · 2017-05-09 08:05:50

763

Views

A compact operator $T$ such that $T^{2}=T$ is a finite rank operator

Published on 09 May 2017 - 8:05

List Question

Show these operators converge to a particular limit

Show the Volterra Operator is compact using only the definition of compact

Let $V\in\mathbb{B}(H,K)$ where $H,K$ are Hilberts spaces. Then $V$ is partial isometry if and only if $V^*$ is partial isometry.

To prove for each sequence $(x_n)$ in $A$ , $T(x_n)$ has a Cauchy subsequence.

Fixed point of compact operator in Banach space

Proving that $K:l_2 \to l_2$ is a compact self-adjoint operator

How will covariance matrix converge to the covariance function, especially in the aspect of eigenvalues and eigenvectors

Universal $C^\ast$-algebra generated by the unilateral shift.

why is it a compact operator

What is the closure of the space of compact operators , on Hilbert space , in the space of bounded operators , under strong operator topology ?

$H$ be a complex Hilbert space , $T: H \to H$ be a compact operator , if $c$ is a eigen-value of $T$ , is $\bar c$ an eigenvalue of $T^*$?

Prove that the following operator is compact.

Non-compact operator with compact derivative

Question on why Hilbert-Schmidt operator definition is independent of the choice of basis

A compact operator $T$ such that $T^{2}=T$ is a finite rank operator

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