Question

$K(X,Y)$ a closed subset of $B(X,Y)$ for normed spaces $X,Y$

score 208 · Answer 1 · 2026-04-15 18:15:40

208

Views

$K(X,Y)$ a closed subset of $B(X,Y)$ for normed spaces $X,Y$

Published on 15 Apr 2026 - 18:15

score 291 · Answer 2 · 2026-04-15 07:12:46

291

Views

A Linear map $‎u : X ‎\longrightarrow ‎Y‎‎$ ‎ ‎is ‎not ‎bounded ‎below ‎‎iff ‎there ‎is ...

Published on 15 Apr 2026 - 7:12

score 1.2k · Answer 3 · 2026-04-10 14:03:42

1.2k

Views

Eigenvalues integral operator - general case

Published on 10 Apr 2026 - 14:03

score 565 · Answer 4 · 2026-04-16 09:17:37

565

Views

What is the spectral radius of the operator $T_k:C[0,1]\to C[0,1]$ defined as $T_k x (t)= \int_0^1 k(t,s) x(s) ds$?

Published on 16 Apr 2026 - 9:17

score 144 · Answer 5 · 2026-04-15 13:27:23

144

Views

If limit of $f(n)$ is zero then the operator is compact

Published on 15 Apr 2026 - 13:27

score 98 · Answer 6 · 2026-04-16 10:06:32

98

Views

Given $F:X \to X$ on $X$:Hilbert space satisfying some properties, prove that $F$ is surjective.

Published on 16 Apr 2026 - 10:06

score 2.9k · Answer 7 · 2026-04-11 21:12:29

2.9k

Views

There are compact operators that are not norm-limits of finite-rank operators

Published on 11 Apr 2026 - 21:12

score 210 · Answer 8 · 2026-04-13 12:32:42

210

Views

Show compactness of an operator and calculate its SVD

Published on 13 Apr 2026 - 12:32

score 1.3k · Answer 9 · 2026-04-12 12:52:12

1.3k

Views

Fredholm and Compact Operators

Published on 12 Apr 2026 - 12:52

score 764 · Answer 10 · 2026-04-13 10:47:18

764

Views

Compactness of multiplication operator on $C[0,1]$

Published on 13 Apr 2026 - 10:47

score 360 · Answer 11 · 2026-04-09 01:06:52

360

Views

Proof of compactness of bounded linear operator

Published on 09 Apr 2026 - 1:06

score 94 · Answer 12 · 2026-04-17 05:44:16

‎‎$‎T:\ell^{‎2‎} \rightarrow ‎\ell^{‎2‎}‎$ ‎‎defined ‎by ‎‎$‎T(\{x_{n}\})=\{2^{-n}x_{n}\}$ ‎is ‎compact

score 156 · Answer 13 · 2026-04-11 12:19:43

156

Views

Continuous, selfadjoint and compact?

Published on 11 Apr 2026 - 12:19

score 136 · Answer 14 · 2026-04-15 14:28:07

136

Views

1.4.5 ‎Theorem ‎of‎ ‎Murphy's ‎book

Published on 15 Apr 2026 - 14:28

score 2k · Answer 15 · 2026-04-09 01:55:45

2k

Views

compact and self adjoint square root of an operator

Published on 09 Apr 2026 - 1:55

List Question

$K(X,Y)$ a closed subset of $B(X,Y)$ for normed spaces $X,Y$

A Linear map $‎u : X ‎\longrightarrow ‎Y‎‎$ ‎ ‎is ‎not ‎bounded ‎below ‎‎iff ‎there ‎is ...

Eigenvalues integral operator - general case

What is the spectral radius of the operator $T_k:C[0,1]\to C[0,1]$ defined as $T_k x (t)= \int_0^1 k(t,s) x(s) ds$?

If limit of $f(n)$ is zero then the operator is compact

Given $F:X \to X$ on $X$:Hilbert space satisfying some properties, prove that $F$ is surjective.

There are compact operators that are not norm-limits of finite-rank operators

Show compactness of an operator and calculate its SVD

Fredholm and Compact Operators

Compactness of multiplication operator on $C[0,1]$

Proof of compactness of bounded linear operator

‎‎$‎T:\ell^{‎2‎} \rightarrow ‎\ell^{‎2‎}‎$ ‎‎defined ‎by ‎‎$‎T(\{x_{n}\})=\{2^{-n}x_{n}\}$ ‎is ‎compact

Continuous, selfadjoint and compact?

1.4.5 ‎Theorem ‎of‎ ‎Murphy's ‎book

compact and self adjoint square root of an operator

Trending Questions

Popular # Hahtags

Popular Questions