Question

Solving complex roots

score 49 · Answer 1 · 2019-04-23 16:52:22

49

Views

Solving complex roots

Published on 23 Apr 2019 - 16:52

score 81 · Answer 2 · 2019-04-23 21:26:57

81

Views

Advanced Complex numbers

Published on 23 Apr 2019 - 21:26

score 36 · Answer 3 · 2019-04-24 14:52:26

36

Views

convergence and absolute convergence of a complex serie

Published on 24 Apr 2019 - 14:52

score 49 · Answer 4 · 2026-03-27 15:16:30

49

Views

exponentiating a matrix with complex elements

Published on 27 Mar 2026 - 15:16

score 61 · Answer 5 · 2026-03-25 18:53:53

61

Views

Convergence & absolute convergence of a complex series

Published on 25 Mar 2026 - 18:53

score 1.1k · Answer 6 · 2026-03-29 10:14:39

1.1k

Views

Complex numbers $z=-3-4i$ polar form

Published on 29 Mar 2026 - 10:14

score 57 · Answer 7 · 2019-04-25 17:48:50

57

Views

Complex plane conundrum

Published on 25 Apr 2019 - 17:48

score 24 · Answer 8 · 2026-04-02 21:40:36

24

Views

Circles in the case of $Distance=\sqrt{x^2+y^2}$, with $x$ as a real number, and $y$ as a real multiple of $a+bi$, with $a$ and $b$ as constants

Published on 02 Apr 2026 - 21:40

score 68 · Answer 9 · 2019-04-26 03:42:44

68

Views

A Challenging Problem in Complex Analysis

Published on 26 Apr 2019 - 3:42

score 148 · Answer 10 · 2019-04-26 10:07:49

148

Views

Value of $|z_{1}|^2+|z_{2}|^2+|z_{3}|^2$ is

Published on 26 Apr 2019 - 10:07

score 104 · Answer 11 · 2019-04-26 10:38:18

104

Views

Check my proof for equality in general triangle equality

Published on 26 Apr 2019 - 10:38

score 1.1k · Answer 12 · 2019-04-26 11:23:54

1.1k

Views

Is multiplying the matrix by its conjugate-transpose and divide by Frobenius norm something special for the matrix itself

Published on 26 Apr 2019 - 11:23

score 56 · Answer 13 · 2019-04-26 15:13:22

56

Views

Show that, for $z \in \mathbb{C}$, $\sqrt{z^2}=\sqrt{x^2}+\frac{x}{|x|}yi$

Published on 26 Apr 2019 - 15:13

score 59 · Answer 14 · 2019-04-26 17:12:35

59

Views

Solve: $ z^5 = \bar{z} * (- \frac{1}{2} + \frac{\sqrt3}{2} i)$. P.S. if $z = x+yi$, $\bar{z} = x - yi$.

Published on 26 Apr 2019 - 17:12

score 124 · Answer 15 · 2026-03-26 01:23:39

124

Views

Showing $\lvert\cos z\rvert^2=a\cos2x+b\cosh2y$, where $z=x+iy$, for numbers $a$ and $b$ to be determined

Published on 26 Mar 2026 - 1:23

List Question

Solving complex roots

Advanced Complex numbers

convergence and absolute convergence of a complex serie

exponentiating a matrix with complex elements

Convergence & absolute convergence of a complex series

Complex numbers $z=-3-4i$ polar form

Complex plane conundrum

Circles in the case of $Distance=\sqrt{x^2+y^2}$, with $x$ as a real number, and $y$ as a real multiple of $a+bi$, with $a$ and $b$ as constants

A Challenging Problem in Complex Analysis

Value of $|z_{1}|^2+|z_{2}|^2+|z_{3}|^2$ is

Check my proof for equality in general triangle equality

Is multiplying the matrix by its conjugate-transpose and divide by Frobenius norm something special for the matrix itself

Show that, for $z \in \mathbb{C}$, $\sqrt{z^2}=\sqrt{x^2}+\frac{x}{|x|}yi$

Solve: $ z^5 = \bar{z} * (- \frac{1}{2} + \frac{\sqrt3}{2} i)$. P.S. if $z = x+yi$, $\bar{z} = x - yi$.

Showing $\lvert\cos z\rvert^2=a\cos2x+b\cosh2y$, where $z=x+iy$, for numbers $a$ and $b$ to be determined

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