List questions from congruences

Published on 12 Sep 2014 - 13:08

86

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Meaning of congruence notation for Bernoulli Numbers

Published on 15 Sep 2014 - 0:46

265

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Congruence modulo n where one side is equal to 1

Published on 15 Sep 2014 - 21:10

58

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Explanation of congruence and modulo

Published on 20 Sep 2014 - 23:30

114

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A combinatorial conjecture

Published on 24 Sep 2014 - 2:55

149

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Solve using Linear Congruences and Divisibility.

Published on 25 Sep 2014 - 11:21

104

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Find the least value of $n$ such that $n^{25}\equiv_{83}37$

Published on 26 Sep 2014 - 20:06

47

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About a new type of congruence system.

Published on 27 Sep 2014 - 4:11

80

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Number of congruence relations of a 4-element non-cyclic group

Published on 29 Sep 2014 - 19:39

1.6k

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Find all integers $k$ such that $k^2\equiv 5k\pmod{15}, 2\leq k\leq 30$.

Published on 01 Oct 2014 - 15:49

179

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Criteria for $p$ being a prime number.

Published on 03 Oct 2014 - 17:27

352

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Can we not apply the Hensel Lifting Lemma in this case?

Published on 04 Oct 2014 - 22:50

147

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Congruences and pigeons

Published on 05 Oct 2014 - 17:33

167

Views

How can I use the congruence property to determine GCD?

Published on 05 Oct 2014 - 23:03

4.3k

Views

If $\gcd(a, 42) = 1$, then $a^6 \equiv 1 \pmod{168}$.

Published on 07 Oct 2014 - 17:42

List Question

How to figure out congruences involving large numbers?

Meaning of congruence notation for Bernoulli Numbers

Congruence modulo n where one side is equal to 1

Explanation of congruence and modulo

A combinatorial conjecture

Solve using Linear Congruences and Divisibility.

Find the least value of $n$ such that $n^{25}\equiv_{83}37$

About a new type of congruence system.

Number of congruence relations of a 4-element non-cyclic group

Find all integers $k$ such that $k^2\equiv 5k\pmod{15}, 2\leq k\leq 30$.

Criteria for $p$ being a prime number.

Can we not apply the Hensel Lifting Lemma in this case?

Congruences and pigeons

How can I use the congruence property to determine GCD?

If $\gcd(a, 42) = 1$, then $a^6 \equiv 1 \pmod{168}$.

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