Question

Proving formula about the least number $n$ such that $a|n$ and $b|(n+1)$, $a,b$ coprime.

score 74 · Answer 1 · 2026-02-24 00:52:11

74

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Proving formula about the least number $n$ such that $a|n$ and $b|(n+1)$, $a,b$ coprime.

Published on 24 Feb 2026 - 0:52

score 267 · Answer 2 · 2026-04-01 14:49:27

267

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Prime Algorithim Conjecture

Published on 01 Apr 2026 - 14:49

score 274 · Answer 3 · 2021-09-01 10:35:50

274

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Trying to prove the Erdős–Straus conjecture

Published on 01 Sep 2021 - 10:35

score 258 · Answer 4 · 2021-09-04 19:33:04

258

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The 'inscribed-circumscribed' 6 point circle

Published on 04 Sep 2021 - 19:33

score 116 · Answer 5 · 2026-03-27 15:18:58

116

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On odd perfect numbers $p^k m^2$ with special prime $p$ satisfying $m^2 - p^k = 2^r t$ - Part III

Published on 27 Mar 2026 - 15:18

score 90 · Answer 6 · 2021-09-07 15:13:44

90

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Conjectures inspired in the context of Casas-Alvero conjecture, via the logarithmic derivative of derivatives of a polynomial

Published on 07 Sep 2021 - 15:13

score 629 · Answer 7 · 2021-09-11 19:03:03

629

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Does Diophantine equation $1+n+n^2+\dots+n^k=2m^2$ have a solution for $n,k \geq 2$?

Published on 11 Sep 2021 - 19:03

score 166 · Answer 8 · 2026-03-26 17:52:41

166

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Potential infinite, fast growing subsequence of twin primes

Published on 26 Mar 2026 - 17:52

score 123 · Answer 9 · 2021-09-22 07:57:23

123

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$p = (u + v)^2 + uv$ for primes $p = 5k \pm 1$?

Published on 22 Sep 2021 - 7:57

score 278 · Answer 10 · 2026-03-27 15:18:58

278

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On odd perfect numbers $p^k m^2$ with special prime $p$ satisfying $m^2 - p^k = 2^r t$ - Part IV

Published on 27 Mar 2026 - 15:18

score 140 · Answer 11 · 2026-03-27 15:19:03

140

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On a possible proof for $p^k < m$, if $p^k m^2$ is an odd perfect number with special prime $p$

Published on 27 Mar 2026 - 15:19

score 236 · Answer 12 · 2026-03-31 21:13:37

236

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Goldbach-like and Collatz-like conjectures and theorems

Published on 31 Mar 2026 - 21:13

score 198 · Answer 13 · 2021-10-04 03:28:10

198

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Using a conjecture to solve a conjecture

Published on 04 Oct 2021 - 3:28

score 139 · Answer 14 · 2026-03-27 15:18:58

139

Views

On odd perfect numbers $p^k m^2$ with special prime $p$ satisfying $m^2 - p^k = 2^r t$ - Part VI

Published on 27 Mar 2026 - 15:18

score 193 · Answer 15 · 2021-10-08 15:51:13

193

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This is a conjecture, refined through previous responses, about sums of positive integers which define sums of the corresponding cubes.

Published on 08 Oct 2021 - 15:51

List Question

Proving formula about the least number $n$ such that $a|n$ and $b|(n+1)$, $a,b$ coprime.

Prime Algorithim Conjecture

Trying to prove the Erdős–Straus conjecture

The 'inscribed-circumscribed' 6 point circle

On odd perfect numbers $p^k m^2$ with special prime $p$ satisfying $m^2 - p^k = 2^r t$ - Part III

Conjectures inspired in the context of Casas-Alvero conjecture, via the logarithmic derivative of derivatives of a polynomial

Does Diophantine equation $1+n+n^2+\dots+n^k=2m^2$ have a solution for $n,k \geq 2$?

Potential infinite, fast growing subsequence of twin primes

$p = (u + v)^2 + uv$ for primes $p = 5k \pm 1$?

On odd perfect numbers $p^k m^2$ with special prime $p$ satisfying $m^2 - p^k = 2^r t$ - Part IV

On a possible proof for $p^k < m$, if $p^k m^2$ is an odd perfect number with special prime $p$

Goldbach-like and Collatz-like conjectures and theorems

Using a conjecture to solve a conjecture

On odd perfect numbers $p^k m^2$ with special prime $p$ satisfying $m^2 - p^k = 2^r t$ - Part VI

This is a conjecture, refined through previous responses, about sums of positive integers which define sums of the corresponding cubes.

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