List questions from continued-fractions

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What is this function related with continued fractions?

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Continued fractions formula

Published on 20 Sep 2018 - 14:32

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description in mathematics

Published on 25 Mar 2026 - 1:13

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forming the continued fraction of the euler number

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Determinants of products of binary matrices and binomial coefficients

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Coefficients of binomial continued fractions

Published on 09 Oct 2018 - 21:27

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Is it true that there are infinitely many square numbers of the form $\lfloor n\sqrt{2}\rfloor$?

Published on 14 Oct 2018 - 12:08

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continued fraction development of the numbers of the following form, $\sqrt{n^2-1}$

Published on 16 Oct 2018 - 13:19

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Finding the limit of the sequence $(1, \frac{1}{2+1}, \frac{1}{2+\frac{1}{1+1}},\cdots)$

Published on 22 Oct 2018 - 14:21

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Book on the Lambert W function.

Published on 24 Mar 2026 - 22:09

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Convergence to $\sqrt{2}$

Published on 31 Oct 2018 - 7:42

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Prove or disprove $aB_m-bA_m=[q_n,\cdots,q_m]$

Published on 04 Nov 2018 - 7:51

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Convergence of the continued fraction [1,1,1,...]

Published on 06 Nov 2018 - 18:50

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Let $C_k = \frac{q_k}{p_k}$ denote the $k^{th}$ convergent of $[a_0;a_1,a_2,\dots]$. Prove that $p_kq_{k-1}-p_{k-1}q_k = (-1)^{k-1}$.

Published on 07 Nov 2018 - 6:12

List Question

Continued fraction involving Fibonacci sequence

What is this function related with continued fractions?

Continued fractions formula

description in mathematics

forming the continued fraction of the euler number

Determinants of products of binary matrices and binomial coefficients

Coefficients of binomial continued fractions

Is it true that there are infinitely many square numbers of the form $\lfloor n\sqrt{2}\rfloor$?

continued fraction development of the numbers of the following form, $\sqrt{n^2-1}$

Finding the limit of the sequence $(1, \frac{1}{2+1}, \frac{1}{2+\frac{1}{1+1}},\cdots)$

Book on the Lambert W function.

Convergence to $\sqrt{2}$

Prove or disprove $aB_m-bA_m=[q_n,\cdots,q_m]$

Convergence of the continued fraction [1,1,1,...]

Let $C_k = \frac{q_k}{p_k}$ denote the $k^{th}$ convergent of $[a_0;a_1,a_2,\dots]$. Prove that $p_kq_{k-1}-p_{k-1}q_k = (-1)^{k-1}$.

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