Question

Finding a cubic equation given four points, elimination not working

score 74 · Answer 1 · 2019-06-12 11:12:04

74

Views

Finding a cubic equation given four points, elimination not working

Published on 12 Jun 2019 - 11:12

score 2.3k · Answer 2 · 2019-06-13 05:50:21

2.3k

Views

Relationship between a determinant and the roots of a cubic equation

Published on 13 Jun 2019 - 5:50

score 100 · Answer 3 · 2019-06-14 11:21:02

100

Views

None of the methods I know to factor cubics are working here ....

Published on 14 Jun 2019 - 11:21

score 130 · Answer 4 · 2026-03-25 13:51:08

130

Views

$ f_3(a,b) $ always a cube integer?

Published on 25 Mar 2026 - 13:51

score 51 · Answer 5 · 2019-06-20 08:01:44

51

Views

Find $x$-coordinate of $Q$ from intersection of curve $y=ax^3$ and its tangent line

Published on 20 Jun 2019 - 8:01

score 133 · Answer 6 · 2019-06-20 17:47:04

133

Views

Linear quadratic cubic system of equation

Published on 20 Jun 2019 - 17:47

score 702 · Answer 7 · 2019-06-27 07:20:22

702

Views

$y=ax^3+bx^2+cx+d$ cubic function, goes through these points $(0,1) ,(-1,-2), (1,2), (2,9)$

Published on 27 Jun 2019 - 7:20

score 135 · Answer 8 · 2019-06-28 08:43:12

135

Views

Solving for the constants of a cubic function where its graph is tangent to the x-axis at x=3

Published on 28 Jun 2019 - 8:43

score 66 · Answer 9 · 2019-06-29 09:53:19

66

Views

Solve$(10+6\sqrt3)^{\frac{1}{3}}-(-10+6\sqrt3)^{\frac{1}{3}}$

Published on 29 Jun 2019 - 9:53

score 61 · Answer 10 · 2019-07-02 13:14:15

61

Views

condition for a cubic equation to have no roots in an interval

Published on 02 Jul 2019 - 13:14

score 70 · Answer 11 · 2019-07-04 19:07:14

70

Views

Find $a+b+c$ when $4abc=(a+3)(b+3)(c+3)$

Published on 04 Jul 2019 - 19:07

score 618 · Answer 12 · 2019-07-07 22:54:58

618

Views

Why does this method for solving cubics seem to fail?

Published on 07 Jul 2019 - 22:54

score 138 · Answer 13 · 2019-07-08 13:12:04

138

Views

Solve $x^{3} = 6+ 3xy - 3 ( \sqrt{2}+2 )^{{1}/{3}} , y^{3} = 9 + 3xy(\sqrt{2}+2)^{{1}/{3}} - 3(\sqrt{2}+2)^{{2}/{3}}$

Published on 08 Jul 2019 - 13:12

score 798 · Answer 14 · 2019-07-08 18:59:01

798

Views

Where is my error in trying to find Pythagorean triples with matching areas?

Published on 08 Jul 2019 - 18:59

score 490 · Answer 15 · 2019-07-12 06:12:27

490

Views

Find a new cubic equation with new roots $\alpha\beta$, $\beta\gamma$ and $\gamma\alpha$. Can I use substitution for this?

Published on 12 Jul 2019 - 6:12

List Question

Finding a cubic equation given four points, elimination not working

Relationship between a determinant and the roots of a cubic equation

None of the methods I know to factor cubics are working here ....

$ f_3(a,b) $ always a cube integer?

Find $x$-coordinate of $Q$ from intersection of curve $y=ax^3$ and its tangent line

Linear quadratic cubic system of equation

$y=ax^3+bx^2+cx+d$ cubic function, goes through these points $(0,1) ,(-1,-2), (1,2), (2,9)$

Solving for the constants of a cubic function where its graph is tangent to the x-axis at x=3

Solve$(10+6\sqrt3)^{\frac{1}{3}}-(-10+6\sqrt3)^{\frac{1}{3}}$

condition for a cubic equation to have no roots in an interval

Find $a+b+c$ when $4abc=(a+3)(b+3)(c+3)$

Why does this method for solving cubics seem to fail?

Solve $x^{3} = 6+ 3xy - 3 ( \sqrt{2}+2 )^{{1}/{3}} , y^{3} = 9 + 3xy(\sqrt{2}+2)^{{1}/{3}} - 3(\sqrt{2}+2)^{{2}/{3}}$

Where is my error in trying to find Pythagorean triples with matching areas?

Find a new cubic equation with new roots $\alpha\beta$, $\beta\gamma$ and $\gamma\alpha$. Can I use substitution for this?

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