Question

Intuitive meaning of $d^2=0$ for differential forms / de Rham theory

score 2k · Answer 1 · 2026-03-29 08:44:37

2k

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Intuitive meaning of $d^2=0$ for differential forms / de Rham theory

Published on 29 Mar 2026 - 8:44

score 75 · Answer 2 · 2017-03-14 15:50:18

75

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Calculate $ r^\omega $ and show that $ \int _{[c,d]} r^\omega = \int _{[a,b]} \omega $.

Published on 14 Mar 2017 - 15:50

score 232 · Answer 3 · 2026-03-27 00:59:08

232

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Derivative of an exact form $\omega_t$ is still exact?

Published on 27 Mar 2026 - 0:59

score 460 · Answer 4 · 2017-03-16 09:14:57

460

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Calculate $ \int_\gamma \omega$ where $ \omega(x,y)=\frac{-ydx+xdy}{x^2+y^2} $

Published on 16 Mar 2017 - 9:14

score 109 · Answer 5 · 2026-03-25 23:38:38

109

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Isomorphism between $\Omega_{hor}^{k}\left(P\right)$ and $\Omega^{k}\left(M\right)$

Published on 25 Mar 2026 - 23:38

score 1k · Answer 6 · 2017-03-18 23:33:48

1k

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Pull back of wedge of differential forms

Published on 18 Mar 2017 - 23:33

score 256 · Answer 7 · 2017-03-20 02:16:55

256

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How to define an inner product on $\Lambda^p\mathrm{T}^* M$ for a Riemannian manifold $(M^n,g)$

Published on 20 Mar 2017 - 2:16

score 1.3k · Answer 8 · 2026-03-31 03:28:04

1.3k

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Is every co-closed form co-exact?

Published on 31 Mar 2026 - 3:28

score 1.1k · Answer 9 · 2026-03-29 23:25:55

1.1k

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$\int dzd\bar{z} = \int dz\wedge d\bar{z}$? Double Integration over the complex plane.

Published on 29 Mar 2026 - 23:25

score 825 · Answer 10 · 2026-03-31 03:35:09

825

Views

Relation between Exterior derivative of a section and a Connection on the Vector bundle

Published on 31 Mar 2026 - 3:35

score 221 · Answer 11 · 2017-03-25 08:30:59

221

Views

Cech cohomology

Published on 25 Mar 2017 - 8:30

score 91 · Answer 12 · 2026-03-28 10:40:40

91

Views

Intuition around covering maps and pull backs to degenerate forms

Published on 28 Mar 2026 - 10:40

score 530 · Answer 13 · 2026-03-27 07:13:11

530

Views

Differential of a function and linear form with dual basis vectors

Published on 27 Mar 2026 - 7:13

score 58 · Answer 14 · 2017-03-27 23:13:14

58

Views

Expressions of basis vectors : $\vec{e_{i}}=\dfrac{\partial\vec{OM}}{\partial x^{i}}$ and $\vec{e_{i}}=\dfrac{\partial}{\partial x^{i}}$

Published on 27 Mar 2017 - 23:13

score 206 · Answer 15 · 2017-03-28 18:06:25

206

Views

Why is $\partial\alpha=\overline{\bar{\partial}\bar{\alpha}}$?

Published on 28 Mar 2017 - 18:06

List Question

Intuitive meaning of $d^2=0$ for differential forms / de Rham theory

Calculate $ r^\omega $ and show that $ \int _{[c,d]} r^\omega = \int _{[a,b]} \omega $.

Derivative of an exact form $\omega_t$ is still exact?

Calculate $ \int_\gamma \omega$ where $ \omega(x,y)=\frac{-ydx+xdy}{x^2+y^2} $

Isomorphism between $\Omega_{hor}^{k}\left(P\right)$ and $\Omega^{k}\left(M\right)$

Pull back of wedge of differential forms

How to define an inner product on $\Lambda^p\mathrm{T}^* M$ for a Riemannian manifold $(M^n,g)$

Is every co-closed form co-exact?

$\int dzd\bar{z} = \int dz\wedge d\bar{z}$? Double Integration over the complex plane.

Relation between Exterior derivative of a section and a Connection on the Vector bundle

Cech cohomology

Intuition around covering maps and pull backs to degenerate forms

Differential of a function and linear form with dual basis vectors

Expressions of basis vectors : $\vec{e_{i}}=\dfrac{\partial\vec{OM}}{\partial x^{i}}$ and $\vec{e_{i}}=\dfrac{\partial}{\partial x^{i}}$

Why is $\partial\alpha=\overline{\bar{\partial}\bar{\alpha}}$?

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